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7v^2-41v-6=0
a = 7; b = -41; c = -6;
Δ = b2-4ac
Δ = -412-4·7·(-6)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-43}{2*7}=\frac{-2}{14} =-1/7 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+43}{2*7}=\frac{84}{14} =6 $
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